Question

Can someone please explain to me how to do this!? What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?

Answer 1

PV=nRT
(.98)V=(.485moles)(.0821)296
solve for V

p is for pressure (.98 atm)
you are solving for the volume V
n is moles (.485)
the R value is a constant which is .0821 when your pressure is in atm
T is temperature in Kelvin so add 273 to your celsius temp to get 296