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Find three consecutive integers such that the sum of the first,twice the second, and three times the third is -76

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-14, -13, -12.

This is done by calling the first number x, the second x+1 and the third x+2. Then write the equation using the descriptions as...

x + 2(x+1) + 3(x+2) = -76

Distribute and solve.
User Tadas Davidsonas
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