Question

19) What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?

Answer 1

3 moles

Step-by-step explanation:

200 ml is 1/5 of a liter, so the answer is five times the number of moles present in the solution. 0.6 moles/0.2 liter = x moles/1.0 liter. Solving for x gives 0.2 x = 0.6 or x = 3.0 M.

Answer 2

Answer: 3M

Step-by-step explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute
`KOH` = 0.6 moles

`V_s` = volume of solution in ml= 200 ml

Now put all the given values in the formula of molarity, we get

`Molarity=(0.6moles* 1000)/(200ml)=3mole/L`

Therefore, the molarity of solution will be 3M.