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A gas has a volume of 111 ml at a temperature of 32°c. What volume will the gas occupy at standard temperature?

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From Charle's law the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure.
Therefore V = kT where k is a constant
V1/T1=V2/T2
For standard conditions the temperature is 0 degrees celcius;
Thus; V1= 111 ml, T1 = 32 +273= 305 K, V2= ? T2= 273
Hence; 111/305=V2/ 273
V2= (111× 273)/305
= 99.354 ml

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