Question

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 3x – 3, and HE = 5y + 4. Find the values of x and y.

x = 5, y = 12
x = 5, y = 9
x = 4, y = 9
x = 9, y = 4

Answer 1

We have that in this case the following equalities are met:
DH = HF
x + 3 = 3y
GH = HE
3x - 3 = 5y + 4
We then have the following system of equations:
x-3y = -3
3x-5y = 7
Resolving the system graphically we obtain the following values:
x = 9
y = 4
Note: see attached image.
Answer:
The values of x and y are:
x = 9, y = 4