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A car with a mass of 525kg is being pushed west (left) by a force of 375n from its engine. the coefficient of friction felt by the car is .0420.

a.calculate the force weight of the car.
b.calculate the force friction acting on the car.
c.what is the net force acting on this car?
d.calculate the acceleration of the car.

2 Answers

2 votes

Final answer:

a. The force weight of the car is 5145 N. b. The force friction acting on the car is 216.09 N. c. The net force acting on the car is 158.91 N. d. The acceleration of the car is 0.714 m/s².

Step-by-step explanation:

a. To calculate the force weight of the car, we can use the formula:

Force weight = mass * acceleration due to gravity

Given that the mass of the car (m) is 525 kg and the acceleration due to gravity (g) is 9.8 m/s², we can substitute these values into the formula:

Force weight = 525 kg * 9.8 m/s² = 5145 N

So, the force weight of the car is 5145 N.

b. To calculate the force friction acting on the car, we can use the formula:

Force friction = coefficient of friction * force weight

Given that the coefficient of friction (µ) is 0.0420 and the force weight is 5145 N, we can substitute these values intothe formula:

Force friction = 0.0420 * 5145 N = 216.09 N

So, the force friction acting on the car is 216.09 N.

c. The net force acting on the car can be calculated by subtracting the force friction from the force applied by the engine:

Net force = force applied - force friction

Given that the force applied by the engine is 375 N and the force friction is 216.09 N, we can substitute these values into the formula:

Net force = 375 N - 216.09 N = 158.91 N

So, the net force acting on the car is 158.91 N.

d. To calculate the acceleration of the car, we can use Newton's second law of motion:

Force = mass * acceleration

Given that the force applied by the engine is 375 N and the mass of the car is 525 kg, we can substitute these values into the formula:

375 N = 525 kg * acceleration

Solving for acceleration:

acceleration = 375 N / 525 kg = 0.714 m/s²

So, the acceleration of the car is 0.714 m/s².

User Gregmacfarlane
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4 votes

Step-by-step explanation:

It is given that,

Mass of the car, m = 525 kg

Applied force, F = 375 N

The coefficient of friction felt by the car is 0.42,
\mu=0.42

(a) The weight of the car is given by :


W=mg


W=525* 9.8

W = 5145 N

(b) The force of friction acts in the opposite direction of motion. It can be calculated as :


f=\mu mg


f=0.42* 5145

f = 2160.9 N

(c) Here, the force of friction is greater than the applied force. As a result, the ball will not moves. So, the net force acting on this car is 0.

(d) As the net force acting on the car is 0. There will be no acceleration in the car.

User ComeRun
by
5.7k points