A line passes through (–7, –5) and (–5, 4).Write an equation for the line in point-slope form.
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Slope m = diffy/diffx
m = 9/2
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y - y1 = m*(x - x1) where (x1,y1) is either point.
Rewrite into any form.
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Or,
| x y 1| |-7 -5 1| = 0 |-5 4 1| --- x*(-5-4) - y*(-7+5) + (-28-25) = 0
-9x + 2y - 53 = 0
2: Answer: The equation of the line in slope-intercept form is y = 92x + 532.
The equation of the line in standard form is 9x−2y=−53 Step-by-step explanation: The slope of the line passing through (−7,−5)and(−5,4) is m=y2−y1x2−x1=4+5−5+7=92 Let the equation of the line in slope-intercept form be y=mx +cory =92x+c The point (-7,-5) will satisfy the equation . So, −5=92⋅ (−7)+corc=632−5=532 Hence the equation of the line in slope-intercept form is y=92x+532. The equation of the line in standard form is y=92x+532.or2y=9x+53 or 9x−2y =−53 {Ans]