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Suppose we are told that the acceleration a of a particle moving with uniform speed v in a circle of radius r is proportional to some power of r, say rn, and some power of v, say vm. Determine the values of n and m and write the simplest form of an equation for the acceleration.

User Benee
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2 Answers

3 votes
The equation:

a = r^nv^m

The units for that equation must be:

((m)/(s^2)) = (m)^(-1) ( (m)/(s) )^2
User Arun Aravind
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7.1k points
7 votes

Answer:

Acceleration,
a=k(v^2)/(r)

Step-by-step explanation:

It is given that, the acceleration a of a particle moving with uniform speed v in a circle of radius r is proportional to some power of r and some power of v. Mathematically, it can be written as :


a\propto r^nv^m

or


a=r^nv^m...........(1)

Dimensional formula of a =
[LT^(-2)]

Dimensional formula of r =
[L]

Dimensional formula of v =
[LT^(-1)]

Using dimensional analysis in equation (1) as :


[LT^(-2)]=[L]^n[LT^(-1)]^m


[LT^(-2)]=[L]^(n+m)[T^(-m)]

Equation both sides of equation as :

n + m = 1, m = 2

This gives, n = -1

Use the value of m and n in equation (1) in order to get the formula :


a=kr^(-1)v^2


a=k(v^2)/(r)

Hence, this is the required solution.

User Youssef Elhayani
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6.3k points