Question

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

Answer 1

7(2) + 30 = 14+30 = 44
3(2^2) -5(2)+20 = 12 - 10 + 20 = 22
4(2^2) +8(2) = 16 + 16 = 32

P = 31 + 44 + 22 + 32 = 129

answer
129 inches

Answer 2

Perimeter is 129 inches.

Explanation:

We are given,

A quadrilateral with sides lengths
`(4x^2+8x),(3x^2-5x+20),(7x+30),31` inches.

Now, the values of the side lengths when x = 2 are,

`(4x^2+8x)=(4* 2^2+8* 2)=(4* 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3* 2^2-5* 2+20)=(3* 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7* 2+30)=14+30=44\ inch`

Since, Perimeter of a quadrilateral = Sum of its sides.

Then, Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches.

Hence, the perimeter is 129 inches.