Question

Find the perimeter of the quadrilateral. if x = 2 the perimeter is

Answer 1

Explanation:

Since perimeter of any polygon is represented by sum of its all sides.

Therefore, perimeter of the given quadrilateral = (4x² + 8x) + (3x² - 5x + 20) + (7x + 30) + 31

4x

Answer 2

the perimeter of any shape is equal to the sum of its sides.
then
`the perimeter=31+(4x^(2)+8x)+(7x+30)+(3x^(2)-5x+20)`

`the perimeter= (4x^(2)+3x^(2))+(7x+8x-5x)+20+30+31=7<span>x^(2)+10x+81`
for x=2

`the perimeter= 7*(2)^(2)+10*2+81=7*4+20+81=28+101=129`

Note:
Please double check the substitution but the procedure is 100% right.