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Find the perimeter of the quadrilateral. if x = 2 the perimeter is

Find the perimeter of the quadrilateral. if x = 2 the perimeter is-example-1

2 Answers

1 vote

Answer:

Explanation:

Since perimeter of any polygon is represented by sum of its all sides.

Therefore, perimeter of the given quadrilateral = (4x² + 8x) + (3x² - 5x + 20) + (7x + 30) + 31

4x

User Matthias Benkard
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3 votes
the perimeter of any shape is equal to the sum of its sides.
then
the perimeter=31+(4x^(2)+8x)+(7x+30)+(3x^(2)-5x+20)

the perimeter= (4x^(2)+3x^(2))+(7x+8x-5x)+20+30+31=7<span>x^(2)+10x+81
for x=2

the perimeter= 7*(2)^(2)+10*2+81=7*4+20+81=28+101=129

Note:
Please double check the substitution but the procedure is 100% right.
User Iskar Jarak
by
8.0k points

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