Two charged parallel plates are 0.25 meters away from each other. The field between the plates is 600 . What is the electric potential difference?

asked Sep 13, 2019 132k views

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5 votes

Answer:

150

Step-by-step explanation:

edg 2022, electric potential difference assignment (slide 4/9)

Ezra answered Sep 16, 2019

by Ezra

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5 votes

E=V/d
V= Ed= 600×0.25= 150v

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