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f(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.

2 Answers

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The real roots are 3 and -3.
Imaginary roots:-
x - (2 - i) = 0
x = 2 -i is one imaginary root and the other is 2 + i
User Rozsazoltan
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2 votes

Answer:

The function has

2 real roots and

2 imaginary roots.

User Amit Gujarathi
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