Question

a rectangular garden has a perimeter of 54 feet. it's length is 3 less than twice its width. write and solve an equation to solve for the gardens dimensions

Answer 1

2(L+W)=54
L=2W-3
Substitute L in the first equation:
2((2W-3)+W)=54.
Divide by 2:
(2W-3)+W=27
Simplify by collecting like terms:
3W-3=27.
Add 3:
3W=30.
Divide by 3 to get that
W=10.
Substitute the L and W relations to get
L=2W-3
L=2*10-3
L=17.
The answers are length is 17 and width is 10.