Let us represent the allowance spent by Noah on Monday by the letter "x".
We know that all the fractions must always add up to 1 in such questions.
Thus, if Noah spent 1/6 of his allowance on Tuesday and 3/6 of it on Friday and he spend x amount on Monday, then these spendings must add up to 1.
In other words,


Thus,


Thus Noah spent a third or
of her allowance on Monday.