Question

Greek architects considered a rectangle whose length was approximately 1.6 times its width to be the most visually appealing. find the length and width of a rectangle constructed in this manner if the sum of the length and width is 130ft

Answer 1

Let
x-------------> the length of a rectangle
y-------------> the width of a rectangle
we know that
x+y=130-----------> equation 1
and
x=1.6y--------------> equation 2

I substitute 2 in 1
(1.6y)+y=130-------------> 2.6y=130------------> y=130/2.6------> y=50 ft
x=1.6y--------> x=1.6*50---------> x=80 ft

the answer is
the length is 80 ft
the width is 50ft