Question

Heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp

Answer 1

It's easiest to start with the point-slope form of an equation,
`y-y_1=m(x-x_1)`, where m is the slope and
`(x_1, y_1)` is the point given.

We have m = 3,
`x_1 = 5`, and
`y_1 = 10`.

We plug in these values to get

`y-10=3(x-5)`.

We now rearrange to get this into slope-intercept form,
`y=mx+b`, by solving for y.


`y=3(x-5)+10\\y=3x-15`

Answer 2

Answer:
y = 3x - 5

Step-by-step explanation:
The equation of the line in slope-intercept form is:
y = mx + c
where:
m is the slope
c is the y-intercept

We are given that the slope is 3. Therefore, the equation now is:
y = 3x + c

Now, we need to get the value of c. To do so, we will substitute with the given point (5,10) in the equation and solve for c as follows:
y = 3x + c
10 = 3(5) + c
10 = 15 + c
c = 10 - 15
c = -5

Based on the above, the equation of the line is:
y = 3x - 5

Hope this helps :)