Question

Find three consecutive natural numbers such that the sum of the first and the second is 15 more than the third

Answer 1

Answer: 16, 17 and 18

Explanation:

Let the consecutive natural numbers be x, x+1, and x+2. We are informed that the sum of the first and the second is 15 more than the third. This will be:

[x + x + 1] = [x + 2] + 15

2x + 1 = x + 2 + 15

2x + 1 = x + 17

2x - x = 17 - 1

x = 16

The numbers are 16, 17 and 18.