Question

How many molecules does 0.773 moles of Ca(OH)2 contain?

Answer 1

From the Avogadro's constant 1 mole of a substance contains 6.022 ×10^23 particles.
Therefore; 1 mole of Ca(OH)2 contains 6.022×10^23 molecules
Thus; 0.773 moles contains;
0.773 × 6.022 ×10^23 molecules
= 4.655 ×10^23 molecules

Answer 2

Hello!

0,773 moles of Ca(OH)₂ contain 4,653 · 10²³ molecules.

To calculate that we need to use the Avogrado Number. This number tells us the number of molecules that are in 1 mol of a substance. The name "Avogrado Number" was given in honor of Amadeo Avogadro, an Italian scientist who studied atomic theory. The number is 6,02· 10²³ molecules/mol. To calculate the number of Ca(OH)₂ molecules we use the following conversion factor:


`nmolecules=0,773 moles Ca(OH)_2* (6,02* 10^(23) molecules Ca(OH)_2 )/(1 mol Ca(OH)_2) \\ \\ =4,653 * 10^(23) molecules Ca(OH)_2`

Have a nice day!