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If ED = 10 and DB = 3x-8, what is the length of EB

1. 32
2. 22
3. 10
4. 20

If ED = 10 and DB = 3x-8, what is the length of EB 1. 32 2. 22 3. 10 4. 20-example-1

2 Answers

1 vote
Based on the picture, we know that ED is equal to DB. Therefore:

2 times ED=EB
2(10)=20

EB is 20
User ShieldOfSalvation
by
7.8k points
4 votes
Answer:
EB = 20 units

Step-by-step explanation:
This question can be solved using two methods:
Method #1:
From the image, we can note that D is the midpoint of EB, therefore, ED = DB
This means that:
EB = 2*10 = 20 units

Method #2:
From the image, we know that ED = DB
We are given that ED = 10 units
Therefore:
DB = 3x - 8 = 10
3x = 18
x = 6
DB = 3(6) - 8 = 18 - 8 = 10 units
EB = EB + DB = 10 + 10 = 20 units

Hope this helps :)
User Alvin Rusli
by
7.8k points

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