Question

A drawer contains 4 red socks, 3 white socks, and 3 blue socks. Without looking, you select a sock at random, replace it, and select a second sock at random. What is the probability that the first sock is blue and the second sock is red?

Answer 1

The probability that the first sock is blue and the second sock is red is:
(3/10) * (4/10)=3/25.

Answer 2

`\texttt{Probability}=(3)/(25)`

Explanation:

Probability is the ratio of number of favorable outcome to total number of outcomes.

Total number of socks = 4 + 3 + 3 = 10

Number of blue socks = 3

Number of red sock = 4

`\texttt{Probability of selecting blue sock}=(3)/(10) \\`

`\texttt{Probability of selecting red sock}=(4)/(10) \\`

For finding the combined probability we need to multiply both the values

`\texttt{Probability that the first sock is blue and the second sock is red}=(3)/(10)* (4)/(10)=(12)/(100)=(3)/(25) \\`

`\texttt{Probability}=(3)/(25)`