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Determine whether each equation has one​ solution, no​ solution, or infinitely many solutions

3/2(2x+6)=3x+9

3x+5=3(x+5)

x+4x+4=3(2x-1)

6x+4x+1=2(5x+1)

User Daniel Faria
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1 Answer

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19 votes

Answer: Let's solve each equation step by step to determine the number of solutions:

3/2(2x+6)=3x+9

First, we distribute the 3/2 on the left side:

3x + 9 = 3x + 9

Subtracting 3x from both sides, we get:

9 = 9

This means that the equation is an identity and is true for all values of x. Therefore, it has infinitely many solutions.

3x+5=3(x+5)

Expanding the right side:

3x + 5 = 3x + 15

Subtracting 3x from both sides, we get:

5 = 15

This is a contradiction, so the equation has no solution.

x+4x+4=3(2x-1)

Simplifying the left side:

5x + 4 = 6x - 3

Adding 3 to both sides and subtracting 5x from both sides, we get:

7 = x

Therefore, the equation has one solution, x = 7.

6x+4x+1=2(5x+1)

Simplifying both sides:

10x + 1 = 10x + 2

Subtracting 10x from both sides, we get:

1 = 2

This is a contradiction, so the equation has no solution.

Explanation:

User Alexey Vagarenko
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3.1k points