Question

A series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. If the generator supplies a voltage of 42 V, what is the magnitude of the current? P

Answer 1

The net effective resistance of 10-ohms and 4-ohms
in series is 14 ohms.

The current in the series loop is I = E/R = 42V/14-ohms = 3 amperes.

Answer 2

Answer : The magnitude of the current is, 3 ampere

Solution :

In a series circuit, the total resistance will be,

`R=R_1+R_2`

`R=10\Omega +4\Omega =14\Omega`

Using coulomb's law,

`V=I* R\\\\I=(V)/(R)`

where,

V = voltage = 42 V

I = electric current

R = resistance = 14 ohms

Now put all the given values in the above formula, we get

`I=(42V)/(14\Omega)=3ampere`

Therefore, the magnitude of the current is, 3 ampere