232k views
3 votes
How many moles of Ca(OH)2 are in 3.5kg of Ca(OH)2? Answer in units of mole

User Gerardnll
by
6.6k points

2 Answers

3 votes
First, you need to convert kg to g.
So, 1 kg =1000g.
3.5 x 1000 = 3500g Ca(OH)2

We need to know the molar mass of Ca(OH)2.
Ca= 40.08 g
O=2(15.999)
H=2(1.0079)

Add them all together and you get 74.0938 g.

Put it in the formula from mass to moles.

# of moles = grams Ca(OH)2 x 1 mol Ca(OH)2
--------------------
molar mass Ca(OH)2

3500 g Ca(OH)2 x 1 mol Ca(OH)2
---------------------
74.0938 g Ca(OH)2

So divide 1/74.0938 and multiply by 3500.

You will get about 47.24 moles Ca(OH)2.

Hope this helps! :)
User Ezennnn
by
6.0k points
0 votes

Answer:

47.3 moles of
Ca(OH)_2 are in 3.5 kilograms of
Ca(OH)_2.

Step-by-step explanation:


n=(m)/(M)

Where:

n = Moles of the compound

m= Given mass of the compound

M = Molar mass of the compound

Mass of the calcium hydroxide, m = 3.5 kg = 3500 g (1kg = 1000 g)

Molar mass of the calcium hydroxide = M = 74 g/mol

Moles of calcium hydroxide = n


n=(3500 g)/(74 g/mol)=47.297 mol\approx 47.3 mol

47.3 moles of
Ca(OH)_2 are in 3.5 kilograms of
Ca(OH)_2.

User MrGildarts
by
5.5k points