Answer:
47.3 moles of
are in 3.5 kilograms of
.
Step-by-step explanation:

Where:
n = Moles of the compound
m= Given mass of the compound
M = Molar mass of the compound
Mass of the calcium hydroxide, m = 3.5 kg = 3500 g (1kg = 1000 g)
Molar mass of the calcium hydroxide = M = 74 g/mol
Moles of calcium hydroxide = n

47.3 moles of
are in 3.5 kilograms of
.