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How many liters of laughing gas are in 0.98 moles stp

How many liters of laughing gas are in 0.98 moles stp-example-1
User Odwori
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2 Answers

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3H2 + N2 ===> 2NH3

GIVEN: 44.8 L of H2 at STP.

answer: mols of N2.

User Michael Butscher
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By applying ideal gas equation,

[tex]P\times V=n\times R\times T[\tex]

Where, P= pressure of gas

V=volume of gas

R=Gas constant

n=Number of moles of gas

T=Temperature

At STP, each gas has a defined value of pressure, volume and temperature.

P= 1 atm

R=0.0821 L atm mol⁻¹ K⁻¹

T= 0°C or 273 K

Putting all the values in the equation will give:

[tex]1\times V=0.98\times 0.0821\times 273[\tex]

V = 22 L

So the answer is 22 L.

User Yau
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