Known :
m1 = 80 kg
v1 = 6 m/s
m2 = 40 kg
Solution :
p1 + p2 = p3
m1 • v1 + m2 • v2 = (m1 + m2) • v
Since body 2 is stationery before collision, then v2 = 0
m1 • v1 = (m1 + m2) • v
(80 kg)(6 m/s) = (80 kg + 40 kg) • v
v = 4 m/s
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