Question

Two very quick questions!!

1) If a pulley system with an actual mechanical advantage of 2 is used in lifting a 2,000 lb. car, what effort would be needed to move the car?


If a pulley system with an actual mechanical advantage of 2,000,000 is used in lifting a 2,000 lb. car, what effort would be needed to move the car?,

Answer 1

The weight lifted by a machine to the applied force on a machine is called mechanical advantage. This is written as Mechanical advantage, M. A, = load(weight)/effort. So for 1) M.A = 2 and load = 2, 000lb = 8896.446N. So 2 = 8896.446/ effort Effort = 8896.446/2 = 4448.48 Similarly for M.A of 2, 000, 000 we have Effort = 8896.446/ 2, 000, 000 = 0.004448

Answer 2

Step-by-step explanation:

1. Mechanical advantage of a pulley system, m = 2

Mechanical advantage of a machine is defined as the ratio of load to the effort force i.e.

`m=(F_L)/(F_E)`

Here,
`F_L=2000\ lb`

`F_E=(F_L)/(m)`

`F_E=(2000\ lb)/(2)`

`F_E=1000\ lb`

Hence, 1000 lb effort will be needed to move the car.

2. Mechanical advantage of a pulley system, m = 2,000,000

Value of load,
`F_L=2000\ lb`

Mechanical advantage,
`m=(F_L)/(F_E)`

`F_E=(F_L)/(m)`

`F_E=(2000\ lb)/(2000000)`

`F_E=0.001\ lb`

Hence, 0.001 lb effort would be needed to move the car.