Final answer:
The proportion of the subsequent generation with brown eyes is 0.91.
Step-by-step explanation:
The proportion of the subsequent generation with brown eyes can be determined using the Hardy-Weinberg equilibrium equation. In this case, the equation is: p^2 + 2pq + q^2 = 1
where p^2 represents the proportion of individuals homozygous dominant for brown eyes (allele BB), 2pq represents the proportion of individuals heterozygous for brown eyes (allele Bb), and q^2 represents the proportion of individuals homozygous recessive for blue eyes (allele bb).
Given that 70% of the population has allele B (brown eyes) and 30% has allele b (blue eyes), we can calculate the proportion of individuals with brown eyes as follows:
p^2 = (0.7)^2 = 0.49
2pq = 2(0.7)(0.3) = 0.42
q^2 = (0.3)^2 = 0.09
Therefore, the proportion of the subsequent generation with brown eyes would be 0.49 (homozygous dominant) + 0.42 (heterozygous) = 0.91.