Question

If 70 percent of the hypothetical population passed along allele b, the dominant allele for brown eyes, and 30 percent passed along allele b, the recessive allele for blue eyes, the proportion of the subsequent generation with brown eyes would be ___________, given the hardy-weinberg equilibrium.

Answer 1

The proportion of the subsequent generation with brown eyes is 0.91.

Step-by-step explanation:

The proportion of the subsequent generation with brown eyes can be determined using the Hardy-Weinberg equilibrium equation. In this case, the equation is: p^2 + 2pq + q^2 = 1
where p^2 represents the proportion of individuals homozygous dominant for brown eyes (allele BB), 2pq represents the proportion of individuals heterozygous for brown eyes (allele Bb), and q^2 represents the proportion of individuals homozygous recessive for blue eyes (allele bb).
Given that 70% of the population has allele B (brown eyes) and 30% has allele b (blue eyes), we can calculate the proportion of individuals with brown eyes as follows:
p^2 = (0.7)^2 = 0.49
2pq = 2(0.7)(0.3) = 0.42
q^2 = (0.3)^2 = 0.09

Therefore, the proportion of the subsequent generation with brown eyes would be 0.49 (homozygous dominant) + 0.42 (heterozygous) = 0.91.

Answer 2

Dominant phenotype will be expressed on homozygous dominant(BB) and heterozygous(Bb) type. Using hardy-Weinberg equilibrium, the percentage of individual with brown eye would be:
homozygous dominant= BB= 70%*70%= 49%
heterozygous = 2Bb= 2* 70%*30%= 42%

Total brown eyes= homozygous dominant+ heterozygous
Total brown eyes= 49%+42%= 91%