24.2k views
4 votes
Can someone check my answer?

For y = x2 − 4x + 3,
Determine if the parabola opens up or down.
State if the vertex will be a maximum or minimum.
Find the vertex.
Find the x-intercepts.
Describe the graph of the equation.
Show all work and use complete sentences to receive full credit.,

1 Answer

5 votes
The equation for a parabola is y = ax^2+ bx + c In this example, y = x^​2 - ​4​x + ​3 a = 1 b = -4 c = 3 Because "a" is a positive number, the parabola will open upwards and the vertex will be a minimum (at the bottom). To find the vertex, use x = -b/2a x = -(-4) / 2 (1) x = 4 / 2 x = 2 Then solve for y using x = 2 y = x^​2 - ​4​x + ​3 y = 2^2 - 4(2) + 3 y = 4 - 8 + 3 y = -1 Therefore the vertex (x,y) is at (2, -1) To find the x intercept, let y = 0 and solve for x. y = x^​2 - ​4​x + ​3 0 = x^​2 - ​4​x + ​3 0 - (x^2 - 4x + 3) = x^2 - 4x + 3 - (x^2 - 4x + 3) -x^2 + 4x - 3 = 0 Factor left side of equation: (-x + 1)(x - 3) = 0 Therefore -x + 1 = 0 or x - 3 = 0 x = 1 or x = 3 The x intercepts are (1,0) and (3,0).
User Pini Reznik
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories