Question

Solve the system of linear equations using the substitution method.

Y = 6x + 11 and 2y - 4x = 14

A. (-1, 5)

B. (-4, 3)

C. (-2, 2)

D. (-4, 4)

Answer 1

Hope this answer helps you a lot

Answer 2

Option A. (-1,5)

`{ \blue{ \tt{x = - 1}}}`

`{ \blue{ \tt{y = 5}}}`

Explanation:

`{ \bold{ \orange{y = 6x + 11}}} \: → \: { \bold{ \green{ {eq}^(n)(1)}}}`

`{ \bold{ \orange{2y - 4x = 14}}} \: →{ \green{ \bold{ {eq}^(n)(2)}}}`

Substitute the value of y in Equation no. (2) then,

`{ \bold{ \orange{2(6x + 11) - 4x = 14}}}`

`{ \bold{ \orange{12x + 22 - 4x = 14}}}`

`{ \bold{ \orange{8x + 22 = 14}}}`

`{ \bold{ \orange{8x = 14 - 22}}}`

`{ \bold{ \orange{8x = - 8}}}`

`{ \bold{ \orange{x = ( - 8)/( \: \: \: 8)}}}`

`{ \bold{ \orange{x = - 1}}}`

Substitute the value of x in Equation no. (1) then,

`{ \bold{ \orange{y = 6x + 11}}}`

`{ \bold{ \orange{y = 6(-1) + 11}}}`

`{ \bold{ \orange{y = -6 + 11}}}`

`{ \bold{ \orange{y = 5}}}`