The general formula for the solutions of a quadratic equation
ax² + bx + c = 0
are given by:
x₁₂ = [- b +- √(b²-4ac) ] / 2a
You have three cases:
1) the radicand is positive: you then have two dinstinct soutions, one with the root added to (-b) and then divided by 2a, and the other one with the root subtracted to (-b) and then divided by 2a.
2) the radicand is negative: you then have no solutions, because the root can't be performed. This case means that the given polynomial is never equal to zero.
3) the radicand is equal to zero: you then have the same value for both the solutions, which is -b/(2a).
Therefore your answer should be: C) when the radicand is equals to zero.