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if 0.582 moles of zinc reacts with excess lead(IV) sulfate how many grams are zinc sulfate would be produced? can someone help me please?,

User Thecanteen
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1 Answer

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Balanced equation:
Pb(SO₄)₂ + 2 Zn → 2 ZnSO₄ + Pb
From the equation we found that 2 moles of Zn form 2 moles of ZnSO₄
so 0.582 mole of Zn will produce 0.582 ZnSO₄
Molar mass of ZnSO₄ = 161.47 g/mole
Mass of ZnSO₄ formed = 161.47 x 0.582 = 94.0 grams
User Regeter
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