If 0.582 moles of zinc reacts with excess lead(IV) sulfate how many grams are zinc sulfate would be produced? can someone help me please?,

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asked Jan 8, 2019 190k views

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Regeter · Answer 1 · 2019-01-15T00:06:09+0000

Balanced equation:
Pb(SO₄)₂ + 2 Zn → 2 ZnSO₄ + Pb
From the equation we found that 2 moles of Zn form 2 moles of ZnSO₄
so 0.582 mole of Zn will produce 0.582 ZnSO₄
Molar mass of ZnSO₄ = 161.47 g/mole
Mass of ZnSO₄ formed = 161.47 x 0.582 = 94.0 grams

If 0.582 moles of zinc reacts with excess lead(IV) sulfate how many grams are zinc sulfate would be produced? can someone help me please?,

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