the correct question is
The sum of 5 consecutive integers is 505. What is the third number in this sequence?
Let
x-----------> first integer
x+1-----------> second integer
x+2-----------> third integer
x+3-----------> fourth integer
x+4-----------> fifth integer
we know that
x+(x+1)+(x+2)+(x+3)+(x+4)=505
then
5x+10=505----------> x=(505-10)/5---------> x=99
therefore
the third integer is (x+2)------> 99+2=101
the answer is 101