Question

What is the equation of the line described below written in slope-intercept form? the line passing through point (0, 0) and parallel to the line whose equation is 3x + 2y - 6 = 0

Answer 1

y=-1.5x or y=-(3/2)x

Answer 2

The slope intercept form of the required line is
`y=(-3)/(2)x`.

Explanation:

If a line is defined as

`Ax+By+C=0` ... (1)

Then the slope of the line is

`m=(-A)/(B)`

The given equation is

`3x+2y-6=0` .... (2)

From (1) and (2), we get

`A=3, B=2, C=-6`

The slope of the line is

`m=(-3)/(2)`

The slope of parallel line is same. So, the slope of required line is -3/2.

The slope intercept form of a line is

`y=mx+b`

Where, m is slope and b is y-intercept.

The slope of required line is -3/2 and y-intercept is at (0,0).

`y=(-3)/(2)x+0`

`y=(-3)/(2)x`

Therefore the slope intercept form of the required line is
`y=(-3)/(2)x`.