Question

An experiment requires 54.6 g of ethylene glycol, a liquid whose density in SI units is 1114 kg/m3. Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume in milliliters of the liquid should be used?

Answer 1

Volume in milliliters of the liquid should be used is 49 mL.

Step-by-step explanation:

Mass of the ethylene glycol = 54.6 g = 0.0546 kg

Density =
`1114 kg/m^3`

Volume of ethylene gylcol = V

`Density=(Mass)/(Volume)`

`1114 kg/m^3=(0.0546 kg)/(V)`

`V=(0.0546 kg)/(1114 kg/m^3)=4.90* 10^(-5) m^3`

`1 m^3=1000 L`

`4.90* 10^(-5) m^3=4.90* 10^(-5)* 1000=4.90* 10^(-2) L=49 ml`

1 L = 1000 mL

Volume in milliliters of the liquid should be used is 49 mL.

Answer 2

Answer: 49.0 cm^3

Step-by-step explanation:

1) formula: density = mass / volume

=> volume = mass / density

2) mass (given) = 54.6 g

3) density (given) = 1114 kg / m^3

conversion of units: 1114 kg/ m^3 * 1000 g/kg * 1 m^3 / (1,000,000 cm^3) = 1.114 g/cm^3

4) calculation:

volume = 54.6 g / 1.114 g/cm^3 = 49.0 cm^3