Answer:
The heat of reaction for the combustion of a mole of Ti in this calorimeter is -16,557.69 kJ/mol.
Step-by-step explanation:
Mass of titanium = 1.000 g
Moles of titanium =
![(1 g)/(47.87 g/mol)=0.0208 mole](https://img.qammunity.org/2019/formulas/chemistry/high-school/d3icww1i216tpbwc7xie111sc7xuribvg0.png)
Heat capacity of the calorimeter ,c= 9.84 kJ/K
Initial temperature of the calorimeter ,T=25°C =298 K
Final temperature of the calorimeter ,T'= 60°C = 333 K
Heat gained by calorimeter = q
![q=c* \Delta T= 9.84 kJ/K*(333K-298 K)=344.4 kJ](https://img.qammunity.org/2019/formulas/chemistry/high-school/bqfufxm1kchu0bexsvwfaedjem58vftst7.png)
Heat of combustion released when 1 g of titanium = -344.4 kJ
Heat if released that is why negative sign is used.
In 1 g of titanium = 0.0208 mole
Heat of combustion of 0.0208 moles of titanium = -344.4 kJ
Heat of combustion of 1 moles of titanium:
![(-344.4 kJ)/(0.0208)=-16,557.69 kJ](https://img.qammunity.org/2019/formulas/chemistry/high-school/bk9q3jcsxk5mr4fpi6qosw3nv7uwa1xaoq.png)
The heat of reaction for the combustion of a mole of Ti in this calorimeter is -16,557.69 kJ/mol.