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He balanced equation for the reaction of acetylene, c2h2, and oxygen in an acetylene torch is 2 c2h2 + 5 o2 → 4 co2 + 2 h2o. in this reaction the number of grams of oxygen required to react with 0.13 g
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He balanced equation for the reaction of acetylene, c2h2, and oxygen in an acetylene torch is 2 c2h2 + 5 o2 → 4 co2 + 2 h2o. in this reaction the number of grams of oxygen required to react with 0.13 g of acetylene is ________.
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Sandro Rey
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Answer: 0.4 g
Step-by-step explanation:
1) Balanced chemical equation:
2) 2C2H2 + 5 O2 → 4CO2 + 2 H2O
3) mole ratios:
2 mol C2h2 : 5 mol O2
4) Convert 0.13 g C2H2 into number of moles
n = mass in grams / molar mass
molar mass C2H2 = 2 *12g/mol + 2*1 g/mol = 26 g/mol
n = 0.13 g / 26 g/mol = 0.005 mol
5) Set the proportion with the unknown
5 mol O2 x
----------------- = ---------------
2 mol C2H2 0.005 mol C2H2
x = 0.005 mol C2H2 * 5 mol O2 / 2 mol C2H2 = 0.0125 mol O2
6) Convert 0.0125 mol O2 to grams
mass = number of moles * molar mass
molar mass of O2 = 32 g/mol
mass = 0.0125 mol * 32 g/mol = 0.4 g
Answer: 0.4 g
Ashirley
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Aug 25, 2019
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