Question

Vitellium (Vi) has the following composition:

Vi–188: 187.9122 amu; 10.861%


Vi–191: 190.9047 amu; 12.428%


Vi–193: 192.8938 amu; 76.711%


Based on this data, what can you predict about the average atomic mass of vitellium?


A.)It will be equal to the arithmetic mean of the masses of the three isotopes.

B.)It will be closer to the mass of Vi–188.

C.)It will be closer to the mass of Vi–193.

D.)It will be equal to the mass of Vi–193.

And I am a PLATO user so I already know it's not A!

Answer 1

c

Step-by-step explanation:

i took the quiz and got 5/5

Answer 2

Answer is: C.)It will be closer to the mass of Vi–193.
Average atomic mass of vitellium =
Ar(Vi-188) · ω(Vi-188) + Ar(Vi-191) · ω(Vi-191) + Ar(Vu-193) · ω(Vi-193).
Average atomic mass of vitellium =
187.9122 amu · 0,10861 + 190.9047 amu · 0,12428 + 192.8938 amu · 0,76711.
Average atomic mass of vitellium = 20,409 + 23,725 + 147,970.
Average atomic mass of vitellium = 192,104.