Question

The efficiency of a ramp is 75%. if the amount of work input is 240 j, what is the amount of useful work output?

Answer 1

180

Step-by-step explanation:

If the work input equals 240 then we follow the equation for work output.

Work output = (work input x efficiency)/100%

Work output = (240 x 75%)/100%

Work output = 180/100%

Work output = 180

Answer 2

the correct answer should be 180 J