Question

No clue what to do. show all steps too please. thanks.

Answer 1

We can create two equations from the information given.

"The perimeter of a rectangular field is 76 m."


`\sf P=l+w`


`\sf 76=l+w`

"The length is 1 m less than double the width."


`\sf l=2w-1`

Let's plug in this for 'l' in the first equation:


`\sf 76=(2w-1)+w`

Combine like terms:


`\sf 76=3w-1`

Add 1 to both sides:


`\sf 77=3w`

Divide 3 to both sides:


`\sf w=\boxed{\sf(77)/(3)}`

Plug this into any equation to find the length:


`\sf 76=l+w`


`\sf 76=l+(77)/(3)`

Subtract 77/3 to both sides:


`\sf (228)/(3)-(77)/(3)=l`


`\sf l=\boxed{\sf(151)/(3)}`

So the width is 77/3 and the length is 151/3. Or we can convert them into mixed numbers:


`\sf 25(2)/(3)`,
`\sf 50(1)/(3)`