Question

a jumbo tablet in the shape of a rectangle has a perimeter of 50 inches. The tablet is 7 inches less wide than it is long. find the length and width of the tablet. help plzz

Answer 1

Length = 16 inches and width = 9 inches

Explanation:

The perimeter of a rectangle table = 50 inches

Rectangle table has equal sides of length and equal sides of width.

Let the length of the table be x.

It is given in the question that the table is 7 inches less wide than it is long.

So width of the table = x - 7

Perimeter = 2(length) + 2(width)

Perimeter = 2(x) + 2(x-7) = 50

= 2x + (2)(x) + (2)(-7) = 50

= 2x + 2x + (-14) = 50

= 4x -14 = 50

= 4x = 64

x = 16

Length = 16 inch Width = 16 - 7 = 9 inches

perimeter = 2(16) + 2(9) = 50 inches

Answer 2

in rectangles, opposite sides are equal.
lets name the length as x
as stated in the question, width is 7 less than the length
therefore length is --> x-7
perimeter = 2*(length) + 2(width)
substituting length and width
perimeter = 2x +2(x-7)
as the perimeter given is 50 inches
70 = 2x + 2x - 14
4x = 84
x = 21 inches
length of tablet - 21 inches
width of tablet - 14 inches