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write the standard form of the line that contains a slope of -3/8 and passes through the point (5,-4)
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write the standard form of the line that contains a slope of -3/8 and passes through the point (5,-4)

User Omeriko
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\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ &&(~ 5 &,& -4) \end{array} \\\\\\ % slope = m slope = m\implies -\cfrac{3}{8} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=-\cfrac{3}{8}(x-5) \\\\\\ y+4=-\cfrac{3}{8}x+\cfrac{15}{8}\implies y=-\cfrac{3}{8}x+\cfrac{15}{8}-4\implies y=-\cfrac{3}{8}x-\cfrac{17}{8}
User Qweezz
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