Answer:
Scott's method is linear because the number of minutes increased by an equal number each week.
Arithmetic progressions use the linear method.
The graph proves it, by obtaining a straight line.
Explanation:
Scott used an arithmetic progression, with a ratio of 5, that is adding 5 to the value of each previous week.
Let us call the time in minutes of each week, so the arithmetic progression is of the following linear form:
S1 = k0 = 10
S2 = k1 + 5 = 10 + 5 = 15
S3 = k2 + 5 = 15 + 5 = 20
S4 = k3 + 5 = 20 + 5 = 25
See attached chart.
Harry used a geometric progression, with a ratio of 2, that is multiplying by 2 the value of each week.
Let us call time in minutes of each week, so the geometric progression is of the following exponential form:
S1 = k0 = 10
S2 = k1 x 2 = 10 x 2 = 20
S3 = k2 x 2 = 20 x 2 = 40
S4 = k3 x 2 = 40 x 2 = 80
See attached chart.
Let's analyze the four options given:
Scott's method is linear because the number of minutes increased by an equal number each week.
True: The graph proves it, by obtaining a straight line.
Also, Arithmetic progressions use the linear method.
Harry's method is linear because the number of minutes increased by an equal factor each week.
False: The graph shows that it is not linear, a straight line is not obtained.
Both Harry and Scott's method are exponential because the number of minutes increases by an equal factor each week.
False: Scott's method is linear.
Both Harry and Scott's method are exponential because the number of minutes increases by an equal number each week.
False: Scott's method is linear.