Question

When p2 – 4p is subtracted from p2 + p – 6, the result is 5p-6 To get p – 9, subtract

Answer 1

We have to subtract
`p^2+3` from the given expression to obtain a difference of
`p-9`

Explanation:

We are given the following information in the question:

We are given an expression:

`p^2 + p -6`

We subtract
`p^2 - 4p` from the given expression.

`p^2 + p -6 - (p^2 - 4p)\\= (p^2 - p^2) + (p + 4p)-6\\=5p - 6`

Now, we want to obtain the difference as
`p-9`

Let x be the expression we subtract from the given expression, then we can write:

`p^2 + p -6 - x = p-9\\p^2 +p -6-(p-9) = x\\x = p^2+(p-p)+(-6+9)\\x = p^2+3`

Thus, we have to subtract
`p^2+3` from the given expression to obtain a difference of
`p-9`

Answer 2

`(p^(2) + p - 6) - (x) = p - 9` is what is asked.

So all you need to do is a value that will result to p - 9.

x =
`(p^(2) + p - 6) - p + 9` To isolate x we just transpose the values from the other side of the equation and do the opposite operation.

Combine like terms and just copy the terms that do not have similar expressions:

p will cancel out because p - p = 0
-6 and + 9 will come together because they are like terms: -6 + 9 = 3

`p^(2)` does not have a pair so it will remain as is. you will be left with:


`p^(2) + 3`

Let us check:


`p^(2) + p - 6`
-
`p^(2) + 0 + 3`
----------------------------

`0 + p - 9` or
`p -9`