Question

Please help thank you very much! :)

Answer 1

Question 1:

First let's compare the side lengths.
Let's make a fraction dividing the larger side and the smaller side.


`(10)/(4) = (5)/(2)`

The larger side is 5/2 times larger than the smaller side.

Note that if two polygons are similar and the side length of one polygon is x times larger than the corresponding side of another polygon, than the area of the larger polygon is x² times larger than the smaller one.

This means that the area of the larger pentagon must be (5/2)² times larger than the smaller one.

A=
`(5/2)^2*30=(25/4)*30=(375)/(2)=187.5`

Your answer is the first choice.

Question 2:

Let's compare the dimensions of both rooms.

`8 \rightarrow 24`

`10 \rightarrow 30`

The larger room has dimensions 3 times larger.
This means that the area of the larger room must be 3² times larger, or 9 times larger.

Multiply the cost of the smaller room by 9.

`350*9=3150`

Your answer is the second choice. Hope this helps! :)