Question

A restaurant offers three vegetable side dishes, two fruit side dishes, and five grain-based side dishes. Each entree comes with two side dishes.

What is the approximate probability of randomly choosing one vegetable and one grain-based side dish?
a.0.08889
b.0.17778
c.0.16667
d.0.33333

Answer 1

D. 0.33333

Explanation:

Answer 2

The approximate probability of randomly choosing one vegetable and one grain-based side dish is: d. 0.33333

Explanation

Vegetable side dishes = 3, Fruit side dishes = 2 and Grain-based side dishes = 5

So, total number of side dishes
`= 3+2+5= 10`

Number of ways for choosing two side dishes from total 10 dishes will be :
`^1^0C_(2)`

We need to randomly choose one vegetable and one grain-based side dish, so the number of ways
`= ^3C_(1) * ^5C_(1)`

Thus, the probability
`= (^3C_(1) * ^5C_(1))/(^1^0C_(2)) = (3*5)/(45)= (15)/(45)= (1)/(3)= 0.3333...`