The answer is 81 decibels
To solve this, we will use the formula : dB = 10 x log (Isig/Iref)
terms will be:dB= decibels,
Isig = signal's intensity
Iref= softest sound's intensity which is 10^-12.
So the solutions is,dB = 10 x log (1.25 x 10–4 / 10^-12 )
= 80.97 decibels
=81 decibels