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If the concentration of h2 is doubled, will the reaction rate quadruple, double, or remain the same?

User Malburrito
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1 Answer

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The answer depends on the rate law.

1) If the rate law is first order on H2, then:

r = K [H2] / A

Since K is a constant and you are not varying A, then the rate will double if [H2] doubles.

2) If the rate law is second order on H2, then:

r = [H2]^2 / A

Again, since K is a constant and you are no varying A, then the rate will quadruple if [H2] is doubled because:

( 2 * [H2] )^2 = 4 [H2]^2

3) If the rate law is of zero order on H2, then the rate will remain the same, because the rate does not depend of the concentration of H2.
User Mon Calamari
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