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5 votes
How many real number solutions does the equation have?

0=5x^2+2x-12
A- one solution
B- two solution
C-infinity many solutions
D-no solutions

User Juan Campa
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2 Answers

4 votes
b is the answer to this
User Vincent Doba
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8.0k points
7 votes
5x^2+2x-12=0 is a quadratic equation. For any ax^2 + bx + c = 0, the solution can be found by completing the square to find the equations
x=(-b+sqrt(b^2-4ac))/2a and x=(-b-sqrt(b^2-4ac))/2a
Substituting using the equation 0=5x^2+2x-12
x=(-2+sqrt(2^2-4(5)(-12)))/(2(5)) and x=(-2+sqrt(2^2-4(5)(-12)))/(2(5))
Since the sqrt(244) is a real number, there are two real solutions.
User Albert Martin
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