2 Answers

Mayang · Answer 1 · 2019-08-18T14:47:41+0000

Answer: The mass of sucrose is 34.23 g

Step-by-step explanation:

Molarity is defined as the number of moles present in one liter of solution.

Mathematically,

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.200 M

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 500 mL

Mass of sucrose = ? g

Putting values in above equation, we get:

$0.200mol/L=\frac{\text{Mass of sucrose}* 1000}{342.3g/mol* 500mL}\\\\\text{Mass of sucrose}=34.23g$

Hence, the mass of sucrose is 34.23 g

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