Question

At what temperature would a 1.50 m nacl solution freeze, given that the van't hoff factor for nacl is 1.9? kf for water is 1.86 ∘c/m .

Answer 1

To determine the freezing point of a 1.50 m NaCl solution, we need to calculate the freezing point depression using the formula: ΔT = Kf × m × i, where ΔT is the freezing point depression, Kf is the freezing point depression constant for water, m is the molality of the solution, and i is the van 't Hoff factor. In this case, the van 't Hoff factor for NaCl is given as 1.9. The freezing point of the solution can be found by subtracting the calculated freezing point depression from the freezing point of pure water.

Step-by-step explanation:

To determine the freezing point of a 1.50 m NaCl solution, we need to calculate the freezing point depression using the formula:

ΔT = Kf × m × i,

where ΔT is the freezing point depression, Kf is the freezing point depression constant for water, m is the molality of the solution, and i is the van 't Hoff factor. In this case, the van 't Hoff factor for NaCl is given as 1.9.

Let's substitute the given values into the formula:

ΔT = 1.86 °C/m × 1.50 m × 1.9,

ΔT = 5.31 °C.

To find the freezing point of the solution, we subtract the calculated freezing point depression from the freezing point of pure water, which is 0 °C:

Freezing point = 0 °C - 5.31 °C = -5.31 °C.

Therefore, the 1.50 m NaCl solution would freeze at a temperature of -5.31 °C.

Answer 2

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